How To Perform Simple Calculations on Mole

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How to perform simple calculations on Mole
A mole is the amount of a substance which contains as many
elementary entities such as atom, molecules and ions as contain in 12g of
carbon-12.
The mole concept is usually illustrated by series of
calculation based problems. Any substance at standard temperature and pressure
(stp) usually is a mole representation in an uncombined state. 1mole of a
substance at STP contains the Avogadro’s constant ( 6.02×1023 Units).
 Mathematically,  mole is 
expressed as the ratio of mass concentration in grams  over the molar mass of a substance in grams
per mole.Students also check out How to carry out titration experiment
Mole       =    Mass concentration in grams / Molar mass in
g/mol
Therefore the unit of Mole is mol or m
Example 1
What is the no of ions present in 12g of
sodium chloride solution?
Solution
Mole = mass/molar mass
Molar mass of NaCl  = 23 + 35.5 = 58.5g/mol
Mass = 12g
Therefore, mole = 12g/58.5g/mole = 0.205mol
The no of ions = mole  x Avogadros constant
0.205mol x 6.02×1023 Units
= 1.2717×1023 ions
Example 2
How
many moles are there in 0.326 g of barium hydroxide?
Ba(OH)2
= 171. That is, one mole of barium hydroxide has a mass of 171 g. As we have
less than 1 gram, we clearly have less than one mole – we’re looking for a
small answer!
Number
of moles = 0.326/171 = 0.00191 mol
Working with reacting
masses – using equations
Example 1
What
mass of iron reacts with 10.0 g of sulphur? [Fe = 56, S = 32]
First
we need the correctly balanced equation:
Fe(s) + S(s) ® FeS(s)
The
equation shows that one mole of sulphur reacts with one mole of iron. We always
need the same number of moles of iron and sulphur. We can work out the number
of moles of sulphur from the mass:
Number
of moles of sulphur = 10.0/32 = 0.313 mol

Number of moles of iron = 0.313 mol (the same as the sulphur)

Mass of iron = 0.313 × 56 = 17.5 g

Example 2
What
mass of magnesium oxide is made when 250 g of oxygen reacts with excess
magnesium? It is important to have an excess of magnesium so that all of the
oxygen reacts. [Mg =24, O =16].

2Mg(s) + O2(g) ® 2MgO(s)
The
equation shows that 1 mole of oxygen produces two moles of magnesium oxide.
There will always be twice as many moles of magnesium oxide as oxygen (or half
as many moles of oxygen compared to magnesium oxide).
Number
of moles of oxygen = 250/32 = 7.81 mol

Number of moles of magnesium oxide = 2 × 7.81 = 15.6 mol (twice as many)

MgO
= 40

Mass of magnesium oxide = 15.6 × 40 = 625 g

More are coming,,,,,just keep in touch.

Read Also:

What is a Standard Solution

How to prepare a Standard Solution of 0.1M Concentration of Sodium hydroxide

What are homologous series

What are Conjugate Base

What Are Organic Compounds ?

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